## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

$E = 7.6\times 10^{5}~J$
We can find the power received by the person's back as: $P = I~A$ $P = (1400~W/m^2)(0.30~m)(0.50~m)$ $P = 210~W$ We can find the energy that falls on the person's back in 1.0 hour as: $E = P~t$ $E = (210~W)(3600~s)$ $E = 7.6\times 10^{5}~J$