Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 20 - Traveling Waves - Exercises and Problems: 17

Answer

The distance between these two points is 2.5 meters.

Work Step by Step

We can find the wavelength of the wave as: $\lambda = \frac{v}{f}$ $\lambda = \frac{340~m/s}{120~Hz}$ $\lambda = 2.83~m$ We can find the distance $\Delta x$ between the two points as: $\lambda = \frac{2\pi~\Delta x}{\Delta \phi}$ $\Delta x = \frac{\lambda ~\Delta \phi}{2\pi}$ $\Delta x = \frac{(2.83~m)~(5.5~rad)}{2\pi}$ $\Delta x = 2.5~m$ The distance between these two points is 2.5 meters.
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