Chapter 2 - Kinematics in One Dimension - Exercises and Problems - Page 64: 21

a) length of the incline $=127.06 m$ b) Time taken $=7.06 s$

Acceleration on inclined plane will be equal to gsin$\theta$ a) We have $2as =v^2 -u^2$ $9.8 *sin(10)* s = 15^2-3^2$ $1.7*s = 216$ $s =127.06 m$ Thus length of the incline $=127.06 m$ b) We have $ v = u+at$ $15 = 3+ 9.8*sin(10)*t$ $ t = \frac {15-3}{1.7} s$ $t= 7.06s$ Time taken $=7.06 s$