Answer
See the detailed answer below.
Work Step by Step
a) The heat transferred into the gas during the processes of:
from 4 to 3 and from 3 to 2.
You can follow the temperature increase or decrease to answer this question fast.
b) $Q_H$ is the heat transferred into the gas during the processes (4 to 3) and (3 to 2).
And $Q_C$ is the heat transferred out of the gas during the processes (2 to 1) and (1 to 4).
c)
$$Q_H=Q_{4\rightarrow3}+Q_{3\rightarrow 2}=(7.09\times 10^5)+(15.19\times 10^5)$$
$$Q_H=\color{red}{\bf 22.28\times 10^5}\;\rm J$$
$$Q_C=Q_{2\rightarrow1}+Q_{1\rightarrow 4}=(21.27\times 10^5)+(5.06\times 10^5)$$
$$Q_C=\color{red}{\bf 26.33\times 10^5}\;\rm J$$
d) We are moving counterclockwise, so the work done is in not out.
$$W_{in}=\text{Closed area}=\Delta P\Delta V$$
$$W_{in}= (3-1)\times 1.013\times 10^5\times (3-1)$$
$$W_{in}=\color{red}{\bf 4.052\times 10^5}\;\rm J$$
e) No, it is not a refrigerator cycle since this cycle uses the work input to transfer heat energy from the hot reservoir to the cold reservoir which is the reverse of a refrigerators.
