Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 19 - Heat Engines and Refrigerators - Exercises and Problems - Page 550: 26

Answer

$Q_H = 2500J$

Work Step by Step

We have $T_H =873K $ and $T_C =293K$ $\eta _{max} = 1- \frac{293}{873}$ $\eta = 0.66$ But given that $\eta = 60\% * \eta_{max}$ $\therefore \eta = 0.4 =40\%$ Also $\eta = W/Q_H$ $0.4 = 1000J/Q_H$ $Q_H = 2500J$
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