Answer
$60.2g$
Work Step by Step
The mass of the ice cube can be determined as follows:
$m=\frac{c_wm_c\Delta T_c}{c_i\Delta T_i+L_i+c_w \Delta T_w}$
We plug in the known values to obtain:
$m=\frac{(4200)(0.3)(30)}{2090(20)+334000+4200(60)}$
$\implies m=0.0602Kg=60.2g$
