Answer
$0.55K$
Work Step by Step
We can find the temperature increase as
$\frac{1}{2}mv^2=cm\Delta T$
This can be rearranged as
$\Delta T=\frac{v^2}{2c}$
We plug in the known values to obtian:
$\Delta T=\frac{(22.2)^2}{2.449}$
This simplifies to:
$\Delta T=0.55K$
