Chapter 17 - Work, Heat, and the First Law of Thermodynamics - Exercises and Problems - Page 498: 34

$994cm^3$

The required volume of water can be determine as follows: $V=\frac{1}{c_w\rho}(\frac{Pt}{\Delta T}-c_im_k)$ We plug in the known values to obtain: $V=\frac{1}{41900(1000)}(\frac{2000\times 3\times 60}{100-20}-449\times 0.75)$ This simplifies to: $V=9.94\times 10^{-4}m^3$ $\implies V=994cm^3$