Answer
$1.8g$
Work Step by Step
We can find the required mas as follows:
$\Delta m=\frac{\pi D^2CM}{4RT}\Delta p$
We plug in the known values to obtain:
$\Delta m=\frac{\pi(0.022)^2(2)(28)}{4(8.31)(293)}(758000-552000)$
$\implies \Delta m=1.8g$
Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)
by Knight, Randall D.
Published by
Pearson
ISBN 10:
0321740904
ISBN 13:
978-0-32174-090-8
Chapter 16 - A Macroscopic Description of Matter - Exercises and Problems - Page 465: 41
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
