Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 16 - A Macroscopic Description of Matter - Exercises and Problems - Page 464: 19

Answer

$2.4\times 10^{22} molecules$

Work Step by Step

We can determine the required number of oxygen molecules as follows: $N=\frac{pVN_A}{RT}$ We plug in the known values to obtain: $N=\frac{(101300)(0.001)(6.02\times 10^{23})}{8.31(310)}$ This simplifies to: $N=2.4\times 10^{22} molecules$
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