Answer
The new temperature is $293^{\circ}C$
Work Step by Step
We can convert the initial temperature $t_1$ to Kelvin;
$K = C+273$
$K = 10+273$
$K = 283$
Therefore;
$t_1 = 283 ~K$
Let $t_2$ be the new temperature of the sample.;
$t_2 = 2t_1$
$t_2 = (2)(283~K)$
$t_2 = 566~K$
We then convert the new temperature to degrees Celsius:
$C = K - 273$
$C = 566 - 273$
$C = 293$
The new temperature is $293^{\circ}C$.
