Answer
See the detailed answer below.
Work Step by Step
To solve this problem, we need to use table 13.2 data.
From the given formula we can see that the first term is a 100-kg block, the second term is the universal gravitational constant, the third term is the mass of the Moon, and the fourth is the moon's radius.
a) A 100-kg block was released from rest above the moon's surface by a distance of $h=1.74\times10^6$ m, what is its speed $v_2$ just before it hits the ground.
b) See the figure below.
c) Solving for $v_2$;
$$v_2=\sqrt{2(6.67\times10^{-11})(7.36\times10^{22})\left[ \dfrac{1}{1.74\times10^6}-\dfrac{1}{3.48\times10^6}\right]}$$
$$v_1=\color{red}{\bf1680}\;\rm m/s$$