Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 12 - Rotation of a Rigid Body - Exercises and Problems: 51

Answer

The speed of a point at the front edge of the wheel is 28 m/s

Work Step by Step

Since the wheel is rolling at 20 m/s, then every point on the wheel has a horizontal component of speed that is equal to 20 m/s and directed forward. If the wheel is rolling at 20 m/s, then every point on the edge of the wheel is rotating with a speed of 20 m/s. From this rotation, a point at the front edge of the wheel has a vertical component of speed that is 20 m/s directed straight down. A point at the front edge of the wheel has a horizontal component of speed equal to 20 m/s and a vertical component of speed equal to 20 m/s. We can find the speed of a point at the front edge of the wheel. $v = \sqrt{(v_x)^2+(v_y)^2}$ $v = \sqrt{(20~m/s)^2+(20~m/s)^2}$ $v = 28~m/s$ The speed of a point at the front edge of the wheel is 28 m/s.
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