Answer
No, the object is not in equilibrium.
Work Step by Step
We can calculate the torque about an axis of rotation perpendicular to the left end of the rod. Note that the 40-N force exerts a torque of zero about this axis.
$\tau = r_1\times F_1+r_2\times F_2$
$\tau = -(2.0~m)(100~N)+(3.0~m)(60~N)$
$\tau = -20~N~m$
Since the torque is non-zero, the object is not in equilibrium.
