Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 12 - Rotation of a Rigid Body - Exercises and Problems: 18

Answer

$\tau_{net} = 0.40~N~m$

Work Step by Step

We can find the magnitude of the net torque on the disk. $\tau_{net} = \sum \tau$ $\tau_{net} = r_1~F_1 - r_2~F_2$ $\tau_{net} = (0.040~m)(30~N)-(0.040~m)(20~N)$ $\tau_{net} = 0.40~N~m$
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