#### Answer

$v = 13.2~m/s$

#### Work Step by Step

We can find the angular velocity of the skater as:
$\omega = (180~rpm)(\frac{1~min}{60~s})(\frac{2\pi~rad}{1~rev})$
$\omega = 6\pi~rad/s$
We then find the speed of the hands. Note that the radius of rotation of the hands is 0.70 meters.
$v = \omega ~r$
$v = (6\pi~rad/s)(0.70~m)$
$v = 13.2~m/s$