Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 12 - Rotation of a Rigid Body - Exercises and Problems - Page 348: 1

Answer

$v = 13.2~m/s$

Work Step by Step

We can find the angular velocity of the skater as: $\omega = (180~rpm)(\frac{1~min}{60~s})(\frac{2\pi~rad}{1~rev})$ $\omega = 6\pi~rad/s$ We then find the speed of the hands. Note that the radius of rotation of the hands is 0.70 meters. $v = \omega ~r$ $v = (6\pi~rad/s)(0.70~m)$ $v = 13.2~m/s$
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