Answer
$112\;\rm km/h$
Work Step by Step
We know that the two vehicles are having the same kinetic energy.
$$K_{car}=K_{truck}$$
Thus,
$$\frac{1}{2}m_{car}v_{car}^2=\frac{1}{2}m_{truck}v_{truck}^2$$
$$ m_{car}v_{car}^2= m_{truck}v_{truck}^2$$
Solving for the $v_{car}$;
$$ v_{car}^2= \dfrac{m_{truck}v_{truck}^2}{m_{car}}$$
$$ v_{car} =\sqrt{ \dfrac{m_{truck}v_{truck}^2}{m_{car}}}$$
Plugging the known;
$$ v_{car} =\sqrt{ \dfrac{20,000\times 25^2}{1000}}\approx \color{red}{\bf 112}\;\rm km/h$$
