# Chapter 8 - Potential Energy and Conservation of Energy - Problems: 128a

9.19 m/s

#### Work Step by Step

The pole is 4.3m long and the firefighter starts at rest. As he falls, his acceleration will be g = 9.81 $m/s^2$ To find his final velocity we use the equation: $v^2 = v_{0}^2 + 2a\Delta x$ we find that v = 9.19 m/s

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