Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 8 - Potential Energy and Conservation of Energy - Problems - Page 212: 127

Answer

The kinetic energy of the clown as he lands in the net is $~~5400~J$

Work Step by Step

We can use conservation of energy to find $K_2$, the kinetic energy of the clown as he lands in the net: $K_2+U_2 = K_1+U_1$ $K_2 = K_1+U_1-U_2$ $K_2 = \frac{1}{2}mv_1^2+mgh_1-mgh_2$ $K_2 = \frac{1}{2}mv_1^2+mg(h_1-h_2)$ $K_2 = \frac{1}{2}(60~kg)(16~m/s)^2+(60~kg)(9.8~m/s^2)(-3.9~m)$ $K_2 = 5400~J$ The kinetic energy of the clown as he lands in the net is $~~5400~J$
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