Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 8 - Potential Energy and Conservation of Energy - Problems - Page 212: 125b

Answer

The rate at which electrical energy could be supplied is $~~2.7\times 10^9~W$

Work Step by Step

We can find the change in gravitational potential energy each second: $\Delta U = mg~\Delta h$ $\Delta U = (5.5\times 10^6~kg)(9.8~m/s^2)(-50~m)$ $\Delta U = -2.7\times 10^9~J$ The decrease in gravitational potential energy each second is $~~-2.7\times 10^9~J$ Note that this amount is the decrease in gravitational potential energy each second. We can find the rate at which electrical energy could be supplied: $P = \frac{E}{t}$ $P = \frac{2.7\times 10^9~J}{1~s}$ $P = 2.7\times 10^9~W$ The rate at which electrical energy could be supplied is $~~2.7\times 10^9~W$
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