## Fundamentals of Physics Extended (10th Edition)

0.227 $m/s^2$
The slope is 200m and with thenew skis it takes 42s to make it down. Since the skier starts at rest, we know that v0 = 0 m/s. Then we can use the equation : $x = x_{0} + v_{0}t + (1/2)at^2$ where we set x = 200, x0 = 0, v0 = 0 and we are solving for the acceleration. We find that it is a = 0.227 $m/s^2$