Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 6 - Force and Motion-II - Problems: 13c

Answer

46N

Work Step by Step

In order for the crate to move when pushed by a force of 110N, it must mean that Ff,max is less than or equal to 110N. Since we know that Ff,max = N*mu and mu is 0.37, this means that the normal force must be equal to 110N/0.37 = 297N. Now that the other worker is pulling up, there are three forces in the y direction, which are the weight of the crate downwards, the Normal force up and the worker pulling up. Thus we have Fnet,y = 0 = F,worker + N - mg. We know that we need N to equal 297N and that the weight is 35kg*9.8 = 343N so we can solve for F,worker and find it to be 46N
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.