Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 5 - Force and Motion-I - Problems: 97b

Answer

$ \sqrt(5) = 2.2$ Newtons

Work Step by Step

Since the vector notation of FNet is Fnet = (1N) i + (-2N) j to find the magnitude we need to use the formula magnitude = $\sqrt(x^2+y^2) $ where x and y are the x and y components (or the i and j components) of the vector, respectively. Therefore we have $\sqrt(1^2 + (-2)^2) = \sqrt (1+4) = \sqrt(5)$
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