## Fundamentals of Physics Extended (10th Edition)

The roof is 2.2m away and the coin initially starts at rest so v0 = 0. Relative to the customer (and therefore, the compartment also since they accelerate at the same rate), the coin is moving upwards at $2.4m/s^2$ To find how long it takes for the coin to travel 2.2m we use $\Delta x = v0*t + (1/2)at^2$ or $2.2 = (1/2)(2.4)t^2$ and find that t = 1.4s