Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 5 - Force and Motion-I - Problems: 2b

Answer

$\vec{a}=(4.0m/s^2)\vec{j}$

Work Step by Step

To find the acceleration, remember that $$\vec{F_{net}}=m\vec{a}$$ This means that the acceleration can be expressed as $$\vec{a}=\frac{\vec{F_{net}}}{m}$$ To find the net force, sum up all forces and their components. This yields a net force of $$\vec{F_{net}}=[(3.0N)\vec{i}+[(4.0N)\vec{j}]+(-3.0N)\vec{i}+(4.0N)\vec{j}]$$ $$\vec{F_{net}}=(8.0N)\vec{j}$$ Therefore, by substituting known values of $F_{net}=(8.0N)\vec{j}$ and $m=2.0kg$ yields an acceleration of $$\vec{a}=\frac{(8.0N)\vec{j}}{2.0kg}=(4.0m/s^2)\vec{j}$$
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