# Chapter 5 - Force and Motion-I - Problems: 2a

(3 $m/s^2$) i + (4$m/s^2$) j

#### Work Step by Step

To find the acceleration on the block, we first need to find the net force. The first force is given as F = (3N)i + (4N)j in part a, the second force is given as F2 = (-3N)i + (-4N)j Adding the two, we have: (3 - - 3)Ni + (4--4)Nj = 6i + 8j = F to find the acceleration, we take a = F/m and m is 2kg. Therefore, a = (6/2)i + (8/2)j = 3i + 4j

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