# Chapter 4 - Motion in Two and Three Dimensions - Problems: 26e

76.5m

#### Work Step by Step

We first need to find the horizontal and vertical components of the velocity using trigonometry and the given angle. Looking at the picture, we can see that Vy can be found as Vx = Vcos($\theta$) where $\theta$ = 40. Therefore, Vx = 15.3m/s. The question asks for the displacement at t = 5s so we can use the velocity and the time elapsed to find that the displacement is (15.3m/s)(5s) = 76.5m

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