## Fundamentals of Physics Extended (10th Edition)

Published by Wiley

# Chapter 4 - Motion in Two and Three Dimensions - Problems: 23a

3.03s

#### Work Step by Step

The gun is fired horizontally, meaning that the bullet has no vertical velocity or that $v_{0y} = 0$. However, it does have vertical acceleration, which is $a_{y} = -9.81 m/s^2$. To find how long it is int he air we use: $y = y_{0} +v_{0y}t + (1/2)at^2$ where $y_{0}$ is the initial height, 45m and y is the final height of 0 when it strikes the ground. $0 = 45 + 0 + (1/2)(-9.81)t^2$ so solving for t we find that it is 3.03s

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