Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 4 - Motion in Two and Three Dimensions - Problems: 21a

Answer

0.18m

Work Step by Step

The dart is thrown horizontally, meaning that it has no velocity in the y component, only in the x (horizontal component). However, it has acceleration in the y direction due to gravity at a = -9.81 $m/s^2$ We can use the equation: $ y = y0 + v_{0y}t + (1/2)a_{y}t^2 $ We can rewrite this as $\Delta y = v_{0y}t + (1/2)a_{y}t^2 $ we know that $v_{0y}$ = 0 as discussed above and a = -9.81$m/s^2$ and the dart takes 0.19 seconds to hit the board (t = 0.1) so $\Delta y = (1/2)(-9.81)(0.19)^2 = 0.18m $ This is how far the dart will drop from the horizontal while it is in flight, and therefore, it is the length of PQ
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