## Fundamentals of Physics Extended (10th Edition)

magnitude = $\sqrt(89) = 9.43m$
The magnitude of a vector is found by the following: magnitude = $\sqrt (x^2 +y^2+z^2)$ where the x, y and z represent the x, y and z components (i, j and k) respectively. In part 1, we found that the position vector in this case is r = -5m i + 8m j Therefore we have x = -5 and y = 8 and z = 0 Plugging these in we have magnitude = $\sqrt ((-5)^2 +8^2+0^2) = \sqrt(25+64) = \sqrt(89)$