## Fundamentals of Physics Extended (10th Edition)

Published by Wiley

# Chapter 4 - Motion in Two and Three Dimensions - Problems: 1a

#### Answer

The magnitude of the vector is $\sqrt (38)m$ or 6.16m

#### Work Step by Step

The magnitude of a vector is given by the formula: magnitude = $\sqrt (x^2 +y^2+z^2)$ where x, y and z represent the x, y, and z components (or i, j, k) respectively. In our case, the vector is (5m)i - (3m)j + (2m)k Therefore x = i = 5, y = j = -3 and z=k = 2 Plugging these in we have magnitude = $\sqrt ((5)^2 +(-3)^2+(2)^2) = \sqrt (25+9+4) = \sqrt (38)$

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