## Fundamentals of Physics Extended (10th Edition)

a avg = 1.58 $m/s^2$
The magnitude of the acceleration is the magnitude of the acceleration vector. Since the vector was $a = -(6/4)i + 0j + (2/4)k$ we can find the magnitude as $\sqrt (i^2 + j^2 +k ^2)$ This gives us $\sqrt ((6/4)^2 + 0^2 + (2/4)^2) = \sqrt(2.25 + 0 + 0.25) = 1.58$