## Fundamentals of Physics Extended (10th Edition)

$\Delta x=8.42m$
First, the speed 303km/h must be converted to meters per second using dimensional analysis. $$\frac{303km}{1hr}\times \frac{1hr}{60min}\times \frac{1min}{60s}\times \frac{1.0km}{1.0\times 10^3m}$$ $$=84.2m/s$$ Use the formula for velocity $$v=\frac{\Delta x}{\Delta t}$$ Solve for $\Delta x$. $$\Delta x =v\Delta t$$ Substitute known values of $t=0.1s$ and $v=84.2m/s$ to get $$\Delta x=(84.2m/s)(0.1s)=8.42m$$