Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 2 - Motion Along a Straight Line - Problems: 101b

Answer

$t=[\sqrt {v^{2}_{0}+2gh}-v_{0}]/g$

Work Step by Step

We know the following equation: $v_{f}=v_{0}+gt$ We substitute the answer from part a: ($v_{f}=\sqrt {v^{2}_{0}+2gh}$): $\sqrt {v^{2}_{0}+2gh}=v_{0}+gt$ We subtract $v_{0}$ from both sides: $\sqrt {v^{2}_{0}+2gh}-v_{0}=gt$ Finally, we divide both sides by $g$: $t=[\sqrt {v^{2}_{0}+2gh}-v_{0}]/g$
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