Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 2 - Motion Along a Straight Line - Problems: 101a

Answer

$v_{f}=\sqrt {v^{2}_{0}+2gh}$

Work Step by Step

This formula is in the reference table ($a$ is replaced with $g$ because acceleration is due to gravity): $v_{f}^{2}={v^{2}_{0}+2gh}$ Algebraically solve for $v_{f}$ : $v_{f}=\sqrt {v^{2}_{0}+2gh}$
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