Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 2 - Motion Along a Straight Line - Problems: 52b

Answer

$v_{f}=37.6m/s$

Work Step by Step

Recall the following equation: $v^{2}_{f}=v^{2}_{0}+2gx$ We plug in the known values to obtain: $v_{f}=\sqrt {v^{2}_{0}+2gx}=\sqrt {(0m/s)^{2}+2(9.8m/s^{2}(90m)(.8)}=37.6m/s$
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