Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 2 - Motion Along a Straight Line - Problems: 51a

Answer

$x=19.6m$

Work Step by Step

The package travels upwards for two seconds with an initial velocity of $19.6m/s$ upwards. The maximum height above the break-free point can be calculated with the equation $v_{f}^{2}=v_{0}^{2}+2gx$. The final velocity at the maximum height is $0$, so the final velocity term reduces to $0$. Solving the equation for x, we get $x=\frac{-v_{0}^{2}}{2g}=\frac{-(19.6m/s)^{2}}{2(-9.8m/s^{2})}=19.6m$
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