## Fundamentals of Physics Extended (10th Edition)

The pipe strikes the ground at a speed of 24m/s. The acceleration due to gravity has a magnitude of $9.8m/s^2$. This means that each second, the velocity increases by 9.8m/s. Since the wrench was dropped, the initial velocity was 0m/s. We use the equation: $v =v0 + at$ Where v0 = initial velocity = 0 We get $24m/s = (9.8 m/s^2)t$ and solving for t we get t = 2.45 seconds