Fundamentals of Physics Extended (10th Edition)

The raindrops fall 1700m and are initially at rest so that v0 = 0m/s. The acceleration on them is that due to gravity, which is $-9.81 m/s^2$ We use the equation: $v^2 = v0^2 + 2a\Delta x$ $v^2 = 0^2 + 2(-9.81)(-1700m)$ ($\Delta x$ is negative because the final height is 0m and the initial height is 1700m so that final height - initial height = -1700m) We find that v = 183 m/s