## Fundamentals of Physics Extended (10th Edition)

In part a we found that it takes 5 seconds for the car to stop. To find the distance traveled in this time we can use the equation: $v^2 = v0^2 + 2a\Delta x$ where again v0 = 24.6m/s, v = 0 and a = -4.92 $m/s^2$ $0 = (24.6)^2 + 2(-4.92)\Delta x$ Solving for $\Delta x$ we find that it is 61.5 m