## Fundamentals of Physics Extended (10th Edition)

The car has a constant deceleration of 4.92 $m/s^2$, meaning that a = -4.92 $m/s^2$. The initial velocity is 24.6m/s and we are interested in how long it takes to come to a stop (v = 0). Therefore we use: $v = v0 + at$ and solve for t $0 = 24.6m/s + (-4.92m/s^2)t$ and we find that t = 5 seconds