Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 2 - Motion Along a Straight Line - Problems: 27b

Answer

17.6 m/s

Work Step by Step

We know the electron has an acceleration of 3.2 $m/s^2 $ and that its velocity at this point in time is 9.6m/s. We call this time t = 0. We are interested in the velocity 2.5 seconds later, or t = 2.5 We use the equation $ v = v0 + at = 9.6m/s + (3.2m/s^2)(2.5s) = 17.6 m/s$
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