Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 2 - Motion Along a Straight Line - Problems: 22b

Answer

$m/s^3$

Work Step by Step

The position is given by $x=ct^2−bt^3 $where x is in meters and t is in time. Since x is in meters, then we know that each of the terms on the right side (since they are subtracted), must have the same units, and must also be in meters. Since we have $bt^3$ and we know that $t^3$ will have units of $s^3$ and we know that overall $bt^3$ must have units of meters, then we have the following: $ m = b*s^3 $ and therefore b has units of $m/s^3$
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