## Fundamentals of Physics Extended (10th Edition)

The position is given by the equation $x = 3t - 4t^2 + t^3$ where x is in meters and t is in seconds To find the position at t = 3 s we need to find x(3), or in other words, plug in 3 for t in the equation. This gives us $x = 3(3) - 4(3)^2 + (3)^3 = 9 - 4*9 + 27 = 0$ Therefore x = 0m