# Chapter 13 - Gravitation - Problems: 3

$F$ = $\frac{GMm}{r^2}$ ${F}{r ^2}$ = ${GMm}$ $r ^2$ = $\frac{GMm}F$ $\sqrt{r ^2}$=${\sqrt\frac{GMm}F}$ $r$ = ${\sqrt\frac{6.67\times{10 ^{-11}} \times 5.5 \times 2.4}{2.3\times 10 ^{-12}}}$ $r$ = $19.02 m$

#### Work Step by Step

1. According to Newton's Law of universal Gravitation $F$ = $\frac{GMm}{r^2}$ 2. We have to find separation that is 'r' between the particles. 3. After shifting '${r ^ 2}$' to left side of equation, we take square root on both sides and then put the values to get the value of 'r' which is 19.02m or after rounded it off you can say 19.0 m

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