## Conceptual Physics (12th Edition)

Published by Addison-Wesley

# Chapter 9 - Think and Solve: 40

#### Answer

$$G \frac{(2m_{1})(2 m_{2})}{d^{2}} = 4 \times G \frac{m_{1} m_{2}}{d^{2}}$$ When the distance stays the same, and the mass of each of the planets is doubled, the gravitational force is four times what it was before.

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