## Conceptual Physics (12th Edition)

$$F_{A}= G \frac{M m}{d^{2}}$$ $$F_{B}= G \frac{(2M) m}{d^{2}} = 2 \times F_{A}$$ $$F_{C}= G \frac{M (2m)}{d^{2}} = 2 \times F_{A}$$ $$F_{D}= G \frac{M (2m)}{(2 d)^{2}} = 0.5 \times F_{A}$$