Conceptual Physics (12th Edition)

Published by Addison-Wesley
ISBN 10: 0321909100
ISBN 13: 978-0-32190-910-7

Chapter 9 - Think and Explain: 83

Answer

The inverse-square nature of gravity tells us that if we are twice as far from the Earth’s center, the gravitational field will be $\frac {1}{4}$ its value at the surface, or $2.5 \frac{m}{s^{2}}$. $$g = G \frac{m_{Earth}}{d^{2}} = (6.67 \times 10^{-11} \frac {N \cdot m^{2}}{kg^{2}}) \frac{6.0 \times 10^{24} kg}{(1.28 \times 10^{7} m)^{2}} = 2.5 \frac{m}{s^{2}} $$
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