Conceptual Physics (12th Edition)

Published by Addison-Wesley
ISBN 10: 0321909100
ISBN 13: 978-0-32190-910-7

Chapter 9 - Think and Explain: 59

Answer

One-quarter the astronaut's weight on Earth.

Work Step by Step

$$Weight_{on Earth}= G \frac{M_{Earth} m}{(d_{Earth})^{2}}$$ $$Weight_{new \;planet}= G \frac{M_{Earth} m}{(2 d_{Earth})^{2}} = \frac{1}{4} \times Weight_{on Earth}$$
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