## Conceptual Physics (12th Edition)

$6.67 \times 10^{-11} N$
$$F= G \frac{m_{1} m_{2}}{d^{2}} =$$ $$(6.67 \times 10^{-11} \frac {N \cdot m^{2}}{kg^{2}}) \frac{(1 kg)(1 kg)}{(1 m)^{2}} =$$ $$6.67 \times 10^{-11} N$$ This is discussed on page 163.